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148155041 is a prime number
BaseRepresentation
bin10001101010010…
…10101010100001
3101022210001111202
420311022222201
5300411430131
622411250545
73446203616
oct1065125241
9338701452
10148155041
11766a2091
1241749a55
1324904208
141596850d
15d017bcb
hex8d4aaa1

148155041 has 2 divisors, whose sum is σ = 148155042. Its totient is φ = 148155040.

The previous prime is 148154977. The next prime is 148155047. The reversal of 148155041 is 140551841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 146410000 + 1745041 = 12100^2 + 1321^2 .

It is a cyclic number.

It is not a de Polignac number, because 148155041 - 26 = 148154977 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 148154995 and 148155013.

It is not a weakly prime, because it can be changed into another prime (148155047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74077520 + 74077521.

It is an arithmetic number, because the mean of its divisors is an integer number (74077521).

Almost surely, 2148155041 is an apocalyptic number.

It is an amenable number.

148155041 is a deficient number, since it is larger than the sum of its proper divisors (1).

148155041 is an equidigital number, since it uses as much as digits as its factorization.

148155041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3200, while the sum is 29.

The square root of 148155041 is about 12171.8955384936. The cubic root of 148155041 is about 529.1418901523.

Subtracting from 148155041 its product of nonzero digits (3200), we obtain a palindrome (148151841).

The spelling of 148155041 in words is "one hundred forty-eight million, one hundred fifty-five thousand, forty-one".