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14828405113 is a prime number
BaseRepresentation
bin11011100111101011…
…11000000101111001
31102021102021000202101
431303311320011321
5220332032430423
610451224103401
71033314235534
oct156365700571
942242230671
1014828405113
11631a280265
122a5a004b61
131524128b12
14a09517a1b
155bbc1b7ad
hex373d78179

14828405113 has 2 divisors, whose sum is σ = 14828405114. Its totient is φ = 14828405112.

The previous prime is 14828405099. The next prime is 14828405129. The reversal of 14828405113 is 31150482841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14160286009 + 668119104 = 118997^2 + 25848^2 .

It is an emirp because it is prime and its reverse (31150482841) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14828405113 - 221 = 14826307961 is a prime.

It is a super-3 number, since 3×148284051133 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14828405173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7414202556 + 7414202557.

It is an arithmetic number, because the mean of its divisors is an integer number (7414202557).

Almost surely, 214828405113 is an apocalyptic number.

It is an amenable number.

14828405113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14828405113 is an equidigital number, since it uses as much as digits as its factorization.

14828405113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30720, while the sum is 37.

Adding to 14828405113 its reverse (31150482841), we get a palindrome (45978887954).

The spelling of 14828405113 in words is "fourteen billion, eight hundred twenty-eight million, four hundred five thousand, one hundred thirteen".