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14836397441 is a prime number
BaseRepresentation
bin11011101000101000…
…10111010110000001
31102021222022002011112
431310110113112001
5220341104204231
610452111253105
71033442204015
oct156424272601
942258262145
1014836397441
116323839a98
122a6081a195
1315259968c8
14a0a5d8545
155bc79992b
hex374517581

14836397441 has 2 divisors, whose sum is σ = 14836397442. Its totient is φ = 14836397440.

The previous prime is 14836397393. The next prime is 14836397501. The reversal of 14836397441 is 14479363841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14240842225 + 595555216 = 119335^2 + 24404^2 .

It is an emirp because it is prime and its reverse (14479363841) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14836397441 is a prime.

It is a super-2 number, since 2×148363974412 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14836397441.

It is not a weakly prime, because it can be changed into another prime (14836397341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7418198720 + 7418198721.

It is an arithmetic number, because the mean of its divisors is an integer number (7418198721).

Almost surely, 214836397441 is an apocalyptic number.

It is an amenable number.

14836397441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14836397441 is an equidigital number, since it uses as much as digits as its factorization.

14836397441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1741824, while the sum is 50.

The spelling of 14836397441 in words is "fourteen billion, eight hundred thirty-six million, three hundred ninety-seven thousand, four hundred forty-one".