Base | Representation |
---|---|
bin | 11011110001011111… |
… | …10101001000010001 |
3 | 1102111011010100121112 |
4 | 31320233311020101 |
5 | 221014120044233 |
6 | 10503324103105 |
7 | 1035333624425 |
oct | 157057651021 |
9 | 42434110545 |
10 | 14910706193 |
11 | 6361783289 |
12 | 2a81694a95 |
13 | 15381b3696 |
14 | a1641cb85 |
15 | 5c4077048 |
hex | 378bf5211 |
14910706193 has 2 divisors, whose sum is σ = 14910706194. Its totient is φ = 14910706192.
The previous prime is 14910706189. The next prime is 14910706231. The reversal of 14910706193 is 39160701941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7643655184 + 7267051009 = 87428^2 + 85247^2 .
It is an emirp because it is prime and its reverse (39160701941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14910706193 - 22 = 14910706189 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14910706193.
It is not a weakly prime, because it can be changed into another prime (14910706093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7455353096 + 7455353097.
It is an arithmetic number, because the mean of its divisors is an integer number (7455353097).
Almost surely, 214910706193 is an apocalyptic number.
It is an amenable number.
14910706193 is a deficient number, since it is larger than the sum of its proper divisors (1).
14910706193 is an equidigital number, since it uses as much as digits as its factorization.
14910706193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 41.
The spelling of 14910706193 in words is "fourteen billion, nine hundred ten million, seven hundred six thousand, one hundred ninety-three".
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