Base | Representation |
---|---|
bin | 1101100011111110011101… |
… | …0101101011100110110001 |
3 | 1221210112201220020002121201 |
4 | 3120333213111223212301 |
5 | 3423303141423024240 |
6 | 51414202442251201 |
7 | 3066223066441660 |
oct | 330774725534661 |
9 | 57715656202551 |
10 | 14911712704945 |
11 | 482a027090021 |
12 | 1809ba64b6b01 |
13 | 8422261a48a4 |
14 | 397a33248dd7 |
15 | 1acd4b84ad9a |
hex | d8fe756b9b1 |
14911712704945 has 16 divisors (see below), whose sum is σ = 20450412316800. Its totient is φ = 10225142694144.
The previous prime is 14911712704937. The next prime is 14911712705047. The reversal of 14911712704945 is 54940721711941.
It is not a de Polignac number, because 14911712704945 - 23 = 14911712704937 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19086606 + ... + 19852504.
It is an arithmetic number, because the mean of its divisors is an integer number (1278150769800).
Almost surely, 214911712704945 is an apocalyptic number.
It is an amenable number.
14911712704945 is a deficient number, since it is larger than the sum of its proper divisors (5538699611855).
14911712704945 is an equidigital number, since it uses as much as digits as its factorization.
14911712704945 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1322184.
The product of its (nonzero) digits is 2540160, while the sum is 55.
The spelling of 14911712704945 in words is "fourteen trillion, nine hundred eleven billion, seven hundred twelve million, seven hundred four thousand, nine hundred forty-five".
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