14912113 has 4 divisors (see below), whose sum is σ = 15229440. Its totient is φ = 14594788.

The previous prime is 14912089. The next prime is 14912137. The reversal of 14912113 is 31121941.

14912113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is the 1577-th star number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121941 = 1213 ⋅25657.

It is an interprime number because it is at equal distance from previous prime (14912089) and next prime (14912137).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14912113 is a prime.

It is a super-2 number, since 2×14912113² = 444742228249538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14912413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158593 + ... + 158686.

It is an arithmetic number, because the mean of its divisors is an integer number (3807360).

Almost surely, 2^14912113 is an apocalyptic number.

It is an amenable number.

14912113 is a deficient number, since it is larger than the sum of its proper divisors (317327).

14912113 is an equidigital number, since it uses as much as digits as its factorization.

14912113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 317326.

The product of its digits is 216, while the sum is 22.

The square root of 14912113 is about 3861.6205147580. The cubic root of 14912113 is about 246.1386014723.

The spelling of 14912113 in words is "fourteen million, nine hundred twelve thousand, one hundred thirteen".