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149263102648993 is a prime number
BaseRepresentation
bin100001111100000100000110…
…001101100010001010100001
3201120111102011021002202110211
4201330010012031202022201
5124031011313234231433
61245242304524254121
743303621554466054
oct4174040615421241
9646442137082424
10149263102648993
1143618143189753
12148a82330a1341
1365395b10913c8
1428c0530a30a9b
15123ca20e5d8cd
hex87c1063622a1

149263102648993 has 2 divisors, whose sum is σ = 149263102648994. Its totient is φ = 149263102648992.

The previous prime is 149263102648987. The next prime is 149263102649041. The reversal of 149263102648993 is 399846201362941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144399084124689 + 4864018524304 = 12016617^2 + 2205452^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-149263102648993 is a prime.

It is a super-2 number, since 2×1492631026489932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (149263102642993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74631551324496 + 74631551324497.

It is an arithmetic number, because the mean of its divisors is an integer number (74631551324497).

Almost surely, 2149263102648993 is an apocalyptic number.

It is an amenable number.

149263102648993 is a deficient number, since it is larger than the sum of its proper divisors (1).

149263102648993 is an equidigital number, since it uses as much as digits as its factorization.

149263102648993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120932352, while the sum is 67.

The spelling of 149263102648993 in words is "one hundred forty-nine trillion, two hundred sixty-three billion, one hundred two million, six hundred forty-eight thousand, nine hundred ninety-three".