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1493123113081 is a prime number
BaseRepresentation
bin10101101110100101000…
…100101010000001111001
312021202000022120002100001
4111232211010222001321
5143430404004104311
63101533054113001
7212605661024365
oct25564504520171
95252008502301
101493123113081
11526259087476
12201463aab761
13aaa54787552
14523a61da2a5
1528c8d79d4c1
hex15ba512a079

1493123113081 has 2 divisors, whose sum is σ = 1493123113082. Its totient is φ = 1493123113080.

The previous prime is 1493123112989. The next prime is 1493123113093. The reversal of 1493123113081 is 1803113213941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1346388915600 + 146734197481 = 1160340^2 + 383059^2 .

It is a cyclic number.

It is not a de Polignac number, because 1493123113081 - 211 = 1493123111033 is a prime.

It is a super-2 number, since 2×14931231130812 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1493123113081.

It is not a weakly prime, because it can be changed into another prime (1493123213081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746561556540 + 746561556541.

It is an arithmetic number, because the mean of its divisors is an integer number (746561556541).

Almost surely, 21493123113081 is an apocalyptic number.

It is an amenable number.

1493123113081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1493123113081 is an equidigital number, since it uses as much as digits as its factorization.

1493123113081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 37.

The spelling of 1493123113081 in words is "one trillion, four hundred ninety-three billion, one hundred twenty-three million, one hundred thirteen thousand, eighty-one".