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1493500003 is a prime number
BaseRepresentation
bin101100100000101…
…0000000001100011
310212002021122211221
41121001100001203
511024314000003
6404110515511
752003353262
oct13101200143
93762248757
101493500003
116a7050726
12358205b97
131aa557818
141024d05d9
158b1b37bd
hex59050063

1493500003 has 2 divisors, whose sum is σ = 1493500004. Its totient is φ = 1493500002.

The previous prime is 1493499967. The next prime is 1493500007. The reversal of 1493500003 is 3000053941.

It is a strong prime.

It is an emirp because it is prime and its reverse (3000053941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1493500003 - 221 = 1491402851 is a prime.

It is a super-2 number, since 2×14935000032 = 4461084517922000018, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1493500007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746750001 + 746750002.

It is an arithmetic number, because the mean of its divisors is an integer number (746750002).

Almost surely, 21493500003 is an apocalyptic number.

1493500003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1493500003 is an equidigital number, since it uses as much as digits as its factorization.

1493500003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 1493500003 is about 38645.8277566932. The cubic root of 1493500003 is about 1143.0583730697.

Adding to 1493500003 its reverse (3000053941), we get a palindrome (4493553944).

The spelling of 1493500003 in words is "one billion, four hundred ninety-three million, five hundred thousand, three".