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14940319417 is a prime number
BaseRepresentation
bin11011110101000001…
…10010111010111001
31102120012211212022121
431322200302322321
5221044210210132
610510302521241
71036143422362
oct157240627271
942505755277
1014940319417
11637746a121
122a8b596221
1315413815ba
14a1a32ab69
155c6976497
hex37a832eb9

14940319417 has 2 divisors, whose sum is σ = 14940319418. Its totient is φ = 14940319416.

The previous prime is 14940319379. The next prime is 14940319421. The reversal of 14940319417 is 71491304941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13155172416 + 1785147001 = 114696^2 + 42251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14940319417 is a prime.

It is not a weakly prime, because it can be changed into another prime (14940319487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7470159708 + 7470159709.

It is an arithmetic number, because the mean of its divisors is an integer number (7470159709).

Almost surely, 214940319417 is an apocalyptic number.

It is an amenable number.

14940319417 is a deficient number, since it is larger than the sum of its proper divisors (1).

14940319417 is an equidigital number, since it uses as much as digits as its factorization.

14940319417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 43.

The spelling of 14940319417 in words is "fourteen billion, nine hundred forty million, three hundred nineteen thousand, four hundred seventeen".