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14940380778 = 234549547387
BaseRepresentation
bin11011110101000010…
…00001111001101010
31102120012221222111020
431322201001321222
5221044214141103
610510304113310
71036144066311
oct157241017152
942505858436
1014940380778
116377501234
122a8b605836
1315413a34cb
14a1a345278
155c6989753
hex37a841e6a

14940380778 has 16 divisors (see below), whose sum is σ = 29887384800. Its totient is φ = 4979023056.

The previous prime is 14940380761. The next prime is 14940380801. The reversal of 14940380778 is 87708304941.

14940380778 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14940380778.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246400 + ... + 300987.

It is an arithmetic number, because the mean of its divisors is an integer number (1867961550).

Almost surely, 214940380778 is an apocalyptic number.

14940380778 is an abundant number, since it is smaller than the sum of its proper divisors (14947004022).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14940380778 is a wasteful number, since it uses less digits than its factorization.

14940380778 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 551941.

The product of its (nonzero) digits is 1354752, while the sum is 51.

It can be divided in two parts, 149403 and 80778, that added together give a triangular number (230181 = T678).

The spelling of 14940380778 in words is "fourteen billion, nine hundred forty million, three hundred eighty thousand, seven hundred seventy-eight".

Divisors: 1 2 3 6 4549 9098 13647 27294 547387 1094774 1642161 3284322 2490063463 4980126926 7470190389 14940380778