Base | Representation |
---|---|
bin | 11011110110001111… |
… | …10000000010000001 |
3 | 1102120221001200020211 |
4 | 31323013300002001 |
5 | 221104313444301 |
6 | 10511305434121 |
7 | 1036326263344 |
oct | 157307600201 |
9 | 42527050224 |
10 | 14950531201 |
11 | 6382204411 |
12 | 2a92a9b941 |
13 | 1543518688 |
14 | a1b82845b |
15 | 5c77e2051 |
hex | 37b1f0081 |
14950531201 has 2 divisors, whose sum is σ = 14950531202. Its totient is φ = 14950531200.
The previous prime is 14950531171. The next prime is 14950531229. The reversal of 14950531201 is 10213505941.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11942118400 + 3008412801 = 109280^2 + 54849^2 .
It is a cyclic number.
It is not a de Polignac number, because 14950531201 - 27 = 14950531073 is a prime.
It is not a weakly prime, because it can be changed into another prime (14950531241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7475265600 + 7475265601.
It is an arithmetic number, because the mean of its divisors is an integer number (7475265601).
Almost surely, 214950531201 is an apocalyptic number.
It is an amenable number.
14950531201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14950531201 is an equidigital number, since it uses as much as digits as its factorization.
14950531201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 14950531201 in words is "fourteen billion, nine hundred fifty million, five hundred thirty-one thousand, two hundred one".
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