Base | Representation |
---|---|
bin | 11011110110100011… |
… | …01101001100011011 |
3 | 1102121002222021020202 |
4 | 31323101231030123 |
5 | 221111001003034 |
6 | 10511441412415 |
7 | 1036360413215 |
oct | 157321551433 |
9 | 42532867222 |
10 | 14953141019 |
11 | 6383727193 |
12 | 2a9393a10b |
13 | 1543c2054b |
14 | a1bd075b5 |
15 | 5c7b5a47e |
hex | 37b46d31b |
14953141019 has 2 divisors, whose sum is σ = 14953141020. Its totient is φ = 14953141018.
The previous prime is 14953141013. The next prime is 14953141031. The reversal of 14953141019 is 91014135941.
It is a weak prime.
It is an emirp because it is prime and its reverse (91014135941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14953141019 - 212 = 14953136923 is a prime.
It is a super-2 number, since 2×149531410192 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (14953141013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7476570509 + 7476570510.
It is an arithmetic number, because the mean of its divisors is an integer number (7476570510).
Almost surely, 214953141019 is an apocalyptic number.
14953141019 is a deficient number, since it is larger than the sum of its proper divisors (1).
14953141019 is an equidigital number, since it uses as much as digits as its factorization.
14953141019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 38.
The spelling of 14953141019 in words is "fourteen billion, nine hundred fifty-three million, one hundred forty-one thousand, nineteen".
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