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14969195553 = 3132913235363
BaseRepresentation
bin11011111000011101…
…11100110000100001
31102122020011220221010
431330032330300201
5221124103224203
610513213451133
71036644030354
oct157416746041
942566156833
1014969195553
1163917a21a4
122a991a0aa9
131547351b80
14a200c629b
155c927c303
hex37c3bcc21

14969195553 has 16 divisors (see below), whose sum is σ = 22235411520. Its totient is φ = 8894163264.

The previous prime is 14969195551. The next prime is 14969195599. The reversal of 14969195553 is 35559196941.

It is not a de Polignac number, because 14969195553 - 21 = 14969195551 is a prime.

It is a super-3 number, since 3×149691955533 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14969195493 and 14969195502.

It is not an unprimeable number, because it can be changed into a prime (14969195551) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6616551 + ... + 6618812.

It is an arithmetic number, because the mean of its divisors is an integer number (1389713220).

Almost surely, 214969195553 is an apocalyptic number.

14969195553 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14969195553 is a deficient number, since it is larger than the sum of its proper divisors (7266215967).

14969195553 is a wasteful number, since it uses less digits than its factorization.

14969195553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13235408.

The product of its digits is 6561000, while the sum is 57.

The spelling of 14969195553 in words is "fourteen billion, nine hundred sixty-nine million, one hundred ninety-five thousand, five hundred fifty-three".

Divisors: 1 3 13 29 39 87 377 1131 13235363 39706089 172059719 383825527 516179157 1151476581 4989731851 14969195553