Base | Representation |
---|---|
bin | 1000101101110101001… |
… | …0010011001100011011 |
3 | 112022111201221210222001 |
4 | 2023131102103030123 |
5 | 4423132302400021 |
6 | 152442410541431 |
7 | 13550506216126 |
oct | 2133522231433 |
9 | 468451853861 |
10 | 149741450011 |
11 | 5856116577a |
12 | 25030137877 |
13 | 11174b351ba |
14 | 73672cb3bd |
15 | 3d6605c091 |
hex | 22dd49331b |
149741450011 has 2 divisors, whose sum is σ = 149741450012. Its totient is φ = 149741450010.
The previous prime is 149741449999. The next prime is 149741450057. The reversal of 149741450011 is 110054147941.
149741450011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-149741450011 is a prime.
It is not a weakly prime, because it can be changed into another prime (149741450311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74870725005 + 74870725006.
It is an arithmetic number, because the mean of its divisors is an integer number (74870725006).
Almost surely, 2149741450011 is an apocalyptic number.
149741450011 is a deficient number, since it is larger than the sum of its proper divisors (1).
149741450011 is an equidigital number, since it uses as much as digits as its factorization.
149741450011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 37.
Adding to 149741450011 its reverse (110054147941), we get a palindrome (259795597952).
The spelling of 149741450011 in words is "one hundred forty-nine billion, seven hundred forty-one million, four hundred fifty thousand, eleven".
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