Base | Representation |
---|---|
bin | 10101110010100110100… |
… | …000101100100011111001 |
3 | 12022011011022200211201021 |
4 | 111302212200230203321 |
5 | 144013230201123433 |
6 | 3103525423222441 |
7 | 213121004520004 |
oct | 25624640544371 |
9 | 5264138624637 |
10 | 1497442207993 |
11 | 5280750a73a6 |
12 | 20226a447a21 |
13 | ab292531204 |
14 | 52695a9453b |
15 | 28e42a5522d |
hex | 15ca682c8f9 |
1497442207993 has 2 divisors, whose sum is σ = 1497442207994. Its totient is φ = 1497442207992.
The previous prime is 1497442207973. The next prime is 1497442208023. The reversal of 1497442207993 is 3997022447941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1390010346169 + 107431861824 = 1178987^2 + 327768^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1497442207993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1497442207913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 748721103996 + 748721103997.
It is an arithmetic number, because the mean of its divisors is an integer number (748721103997).
Almost surely, 21497442207993 is an apocalyptic number.
It is an amenable number.
1497442207993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1497442207993 is an equidigital number, since it uses as much as digits as its factorization.
1497442207993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27433728, while the sum is 61.
The spelling of 1497442207993 in words is "one trillion, four hundred ninety-seven billion, four hundred forty-two million, two hundred seven thousand, nine hundred ninety-three".
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