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149975000753 is a prime number
BaseRepresentation
bin1000101110101100110…
…1001110011010110001
3112100010000102102100112
42023223031032122301
54424122100011003
6152521512431105
713556343321104
oct2135315163261
9470100372315
10149975000753
1158670a83916
12250963a8495
13111b13386c6
14738a32473b
153d7b7e23d8
hex22eb34e6b1

149975000753 has 2 divisors, whose sum is σ = 149975000754. Its totient is φ = 149975000752.

The previous prime is 149975000731. The next prime is 149975000783. The reversal of 149975000753 is 357000579941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102410880289 + 47564120464 = 320017^2 + 218092^2 .

It is a cyclic number.

It is not a de Polignac number, because 149975000753 - 210 = 149974999729 is a prime.

It is a super-3 number, since 3×1499750007533 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (149975000783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74987500376 + 74987500377.

It is an arithmetic number, because the mean of its divisors is an integer number (74987500377).

Almost surely, 2149975000753 is an apocalyptic number.

It is an amenable number.

149975000753 is a deficient number, since it is larger than the sum of its proper divisors (1).

149975000753 is an equidigital number, since it uses as much as digits as its factorization.

149975000753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1190700, while the sum is 50.

The spelling of 149975000753 in words is "one hundred forty-nine billion, nine hundred seventy-five million, seven hundred fifty-three", and thus it is an aban number.