150001022201 has 4 divisors (see below), whose sum is σ = 151146068304. Its totient is φ = 148855976100.

The previous prime is 150001022191. The next prime is 150001022207. The reversal of 150001022201 is 102220100051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150001022201 is a prime.

It is a super-2 number, since 2×150001022201² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (150001022207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 572522855 + ... + 572523116.

It is an arithmetic number, because the mean of its divisors is an integer number (37786517076).

Almost surely, 2^150001022201 is an apocalyptic number.

It is an amenable number.

150001022201 is a deficient number, since it is larger than the sum of its proper divisors (1145046103).

150001022201 is a wasteful number, since it uses less digits than its factorization.

150001022201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1145046102.

The product of its (nonzero) digits is 40, while the sum is 14.

Adding to 150001022201 its reverse (102220100051), we get a palindrome (252221122252).

The spelling of 150001022201 in words is "one hundred fifty billion, one million, twenty-two thousand, two hundred one".