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150008041 is a prime number
BaseRepresentation
bin10001111000011…
…11000011101001
3101110021012100101
420330033003221
5301400224131
622515105401
73501022141
oct1074170351
9343235311
10150008041
1177748297
12422a2261
1325102771
1415ccb921
15d281c61
hex8f0f0e9

150008041 has 2 divisors, whose sum is σ = 150008042. Its totient is φ = 150008040.

The previous prime is 150008011. The next prime is 150008057. The reversal of 150008041 is 140800051.

150008041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 148742416 + 1265625 = 12196^2 + 1125^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150008041 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (150008011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75004020 + 75004021.

It is an arithmetic number, because the mean of its divisors is an integer number (75004021).

Almost surely, 2150008041 is an apocalyptic number.

It is an amenable number.

150008041 is a deficient number, since it is larger than the sum of its proper divisors (1).

150008041 is an equidigital number, since it uses as much as digits as its factorization.

150008041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 150008041 is about 12247.7769819670. The cubic root of 150008041 is about 531.3387786856.

Adding to 150008041 its reverse (140800051), we get a palindrome (290808092).

The spelling of 150008041 in words is "one hundred fifty million, eight thousand, forty-one".