Base | Representation |
---|---|
bin | 1000101110110101101… |
… | …0110011001011101010 |
3 | 112100012121020221122222 |
4 | 2023231122303023222 |
5 | 4424211100114032 |
6 | 152525320114042 |
7 | 13560303632666 |
oct | 2135532631352 |
9 | 470177227588 |
10 | 150012113642 |
11 | 5868aa22326 |
12 | 250a6905922 |
13 | 111b8c310b1 |
14 | 73912258a6 |
15 | 3d7ebc3a12 |
hex | 22ed6b32ea |
150012113642 has 4 divisors (see below), whose sum is σ = 225018170466. Its totient is φ = 75006056820.
The previous prime is 150012113617. The next prime is 150012113651. The reversal of 150012113642 is 246311210051.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 246311210051 = 92993 ⋅2648707.
It can be written as a sum of positive squares in only one way, i.e., 95759921401 + 54252192241 = 309451^2 + 232921^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37503028409 + ... + 37503028412.
Almost surely, 2150012113642 is an apocalyptic number.
150012113642 is a deficient number, since it is larger than the sum of its proper divisors (75006056824).
150012113642 is an equidigital number, since it uses as much as digits as its factorization.
150012113642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75006056823.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 150012113642 its reverse (246311210051), we get a palindrome (396323323693).
The spelling of 150012113642 in words is "one hundred fifty billion, twelve million, one hundred thirteen thousand, six hundred forty-two".
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