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150021245041 is a prime number
BaseRepresentation
bin1000101110110111110…
…1101000100001110001
3112100020020102212120221
42023231331220201301
54424220414320131
6152530243533041
713560444354103
oct2135575504161
9470206385527
10150021245041
1158695099938
12250a998a181
13111baaaa4a5
147392521573
153d808c9411
hex22edf68871

150021245041 has 2 divisors, whose sum is σ = 150021245042. Its totient is φ = 150021245040.

The previous prime is 150021245027. The next prime is 150021245117. The reversal of 150021245041 is 140542120051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125088835041 + 24932410000 = 353679^2 + 157900^2 .

It is an emirp because it is prime and its reverse (140542120051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150021245041 - 27 = 150021244913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 150021244997 and 150021245015.

It is not a weakly prime, because it can be changed into another prime (150021245441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75010622520 + 75010622521.

It is an arithmetic number, because the mean of its divisors is an integer number (75010622521).

Almost surely, 2150021245041 is an apocalyptic number.

It is an amenable number.

150021245041 is a deficient number, since it is larger than the sum of its proper divisors (1).

150021245041 is an equidigital number, since it uses as much as digits as its factorization.

150021245041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1600, while the sum is 25.

Adding to 150021245041 its reverse (140542120051), we get a palindrome (290563365092).

The spelling of 150021245041 in words is "one hundred fifty billion, twenty-one million, two hundred forty-five thousand, forty-one".