Base | Representation |
---|---|
bin | 1000101110110111110… |
… | …1101000100001110001 |
3 | 112100020020102212120221 |
4 | 2023231331220201301 |
5 | 4424220414320131 |
6 | 152530243533041 |
7 | 13560444354103 |
oct | 2135575504161 |
9 | 470206385527 |
10 | 150021245041 |
11 | 58695099938 |
12 | 250a998a181 |
13 | 111baaaa4a5 |
14 | 7392521573 |
15 | 3d808c9411 |
hex | 22edf68871 |
150021245041 has 2 divisors, whose sum is σ = 150021245042. Its totient is φ = 150021245040.
The previous prime is 150021245027. The next prime is 150021245117. The reversal of 150021245041 is 140542120051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125088835041 + 24932410000 = 353679^2 + 157900^2 .
It is an emirp because it is prime and its reverse (140542120051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150021245041 - 27 = 150021244913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 150021244997 and 150021245015.
It is not a weakly prime, because it can be changed into another prime (150021245441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75010622520 + 75010622521.
It is an arithmetic number, because the mean of its divisors is an integer number (75010622521).
Almost surely, 2150021245041 is an apocalyptic number.
It is an amenable number.
150021245041 is a deficient number, since it is larger than the sum of its proper divisors (1).
150021245041 is an equidigital number, since it uses as much as digits as its factorization.
150021245041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1600, while the sum is 25.
Adding to 150021245041 its reverse (140542120051), we get a palindrome (290563365092).
The spelling of 150021245041 in words is "one hundred fifty billion, twenty-one million, two hundred forty-five thousand, forty-one".
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