Base | Representation |
---|---|
bin | 1000101110111000010… |
… | …0010111100011011011 |
3 | 112100020100202120101011 |
4 | 2023232010113203123 |
5 | 4424221342314043 |
6 | 152530345434351 |
7 | 13560465356221 |
oct | 2135604274333 |
9 | 470210676334 |
10 | 150023010523 |
11 | 58696095311 |
12 | 250aa49b9b7 |
13 | 111bb277c59 |
14 | 7392860b11 |
15 | 3d80b2759d |
hex | 22ee1178db |
150023010523 has 2 divisors, whose sum is σ = 150023010524. Its totient is φ = 150023010522.
The previous prime is 150023010517. The next prime is 150023010539. The reversal of 150023010523 is 325010320051.
It is a weak prime.
It is an emirp because it is prime and its reverse (325010320051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150023010523 - 25 = 150023010491 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 150023010494 and 150023010503.
It is not a weakly prime, because it can be changed into another prime (150023013523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75011505261 + 75011505262.
It is an arithmetic number, because the mean of its divisors is an integer number (75011505262).
Almost surely, 2150023010523 is an apocalyptic number.
150023010523 is a deficient number, since it is larger than the sum of its proper divisors (1).
150023010523 is an equidigital number, since it uses as much as digits as its factorization.
150023010523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 22.
Adding to 150023010523 its reverse (325010320051), we get a palindrome (475033330574).
The spelling of 150023010523 in words is "one hundred fifty billion, twenty-three million, ten thousand, five hundred twenty-three".
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