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150025137 = 350008379
BaseRepresentation
bin10001111000100…
…11001110110001
3101110022001210120
420330103032301
5301401301022
622515320453
73501123033
oct1074231661
9343261716
10150025137
117775a119
12422b0129
132510a492
1415cd3c53
15d286d5c
hex8f133b1

150025137 has 4 divisors (see below), whose sum is σ = 200033520. Its totient is φ = 100016756.

The previous prime is 150025133. The next prime is 150025157. The reversal of 150025137 is 731520051.

150025137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150025137 - 22 = 150025133 is a prime.

It is not an unprimeable number, because it can be changed into a prime (150025133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25004187 + ... + 25004192.

It is an arithmetic number, because the mean of its divisors is an integer number (50008380).

Almost surely, 2150025137 is an apocalyptic number.

It is an amenable number.

150025137 is a deficient number, since it is larger than the sum of its proper divisors (50008383).

150025137 is an equidigital number, since it uses as much as digits as its factorization.

150025137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50008382.

The product of its (nonzero) digits is 1050, while the sum is 24.

The square root of 150025137 is about 12248.4748846540. The cubic root of 150025137 is about 531.3589629874.

Adding to 150025137 its reverse (731520051), we get a palindrome (881545188).

The spelling of 150025137 in words is "one hundred fifty million, twenty-five thousand, one hundred thirty-seven".

Divisors: 1 3 50008379 150025137