Search a number
-
+
15003204147 = 329291794427
BaseRepresentation
bin11011111100100001…
…01011101000110011
31102201121011201221200
431332100223220303
5221211310013042
610520430422243
71040536062651
oct157620535063
942647151850
1015003204147
1163a9a10378
122aa8661983
1315513cb5b9
14a24819dd1
155cc248c4c
hex37e42ba33

15003204147 has 12 divisors (see below), whose sum is σ = 21694634520. Its totient is φ = 9991363968.

The previous prime is 15003204131. The next prime is 15003204149. The reversal of 15003204147 is 74140230051.

It is not a de Polignac number, because 15003204147 - 24 = 15003204131 is a prime.

It is a super-2 number, since 2×150032041472 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 15003204147.

It is not an unprimeable number, because it can be changed into a prime (15003204149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 888853 + ... + 905574.

It is an arithmetic number, because the mean of its divisors is an integer number (1807886210).

Almost surely, 215003204147 is an apocalyptic number.

15003204147 is a deficient number, since it is larger than the sum of its proper divisors (6691430373).

15003204147 is a wasteful number, since it uses less digits than its factorization.

15003204147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1795362 (or 1795359 counting only the distinct ones).

The product of its (nonzero) digits is 3360, while the sum is 27.

Adding to 15003204147 its reverse (74140230051), we get a palindrome (89143434198).

The spelling of 15003204147 in words is "fifteen billion, three million, two hundred four thousand, one hundred forty-seven".

Divisors: 1 3 9 929 2787 8361 1794427 5383281 16149843 1667022683 5001068049 15003204147