Base | Representation |
---|---|
bin | 1000101110111010111… |
… | …1111110011111011001 |
3 | 112100021011021100200122 |
4 | 2023232233332133121 |
5 | 4424232304122301 |
6 | 152531434443025 |
7 | 13560664500560 |
oct | 2135657763731 |
9 | 470234240618 |
10 | 150034442201 |
11 | 586a1593086 |
12 | 250b2293475 |
13 | 111c074b367 |
14 | 7394198bd7 |
15 | 3d81b3481b |
hex | 22eebfe7d9 |
150034442201 has 4 divisors (see below), whose sum is σ = 171467933952. Its totient is φ = 128600950452.
The previous prime is 150034442189. The next prime is 150034442269. The reversal of 150034442201 is 102244430051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102244430051 = 31 ⋅3298207421.
It is a cyclic number.
It is not a de Polignac number, because 150034442201 - 210 = 150034441177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (150034441201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10716745865 + ... + 10716745878.
It is an arithmetic number, because the mean of its divisors is an integer number (42866983488).
Almost surely, 2150034442201 is an apocalyptic number.
It is an amenable number.
150034442201 is a deficient number, since it is larger than the sum of its proper divisors (21433491751).
150034442201 is an equidigital number, since it uses as much as digits as its factorization.
150034442201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21433491750.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 150034442201 its reverse (102244430051), we get a palindrome (252278872252).
The spelling of 150034442201 in words is "one hundred fifty billion, thirty-four million, four hundred forty-two thousand, two hundred one".
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