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150034442201 = 721433491743
BaseRepresentation
bin1000101110111010111…
…1111110011111011001
3112100021011021100200122
42023232233332133121
54424232304122301
6152531434443025
713560664500560
oct2135657763731
9470234240618
10150034442201
11586a1593086
12250b2293475
13111c074b367
147394198bd7
153d81b3481b
hex22eebfe7d9

150034442201 has 4 divisors (see below), whose sum is σ = 171467933952. Its totient is φ = 128600950452.

The previous prime is 150034442189. The next prime is 150034442269. The reversal of 150034442201 is 102244430051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102244430051 = 313298207421.

It is a cyclic number.

It is not a de Polignac number, because 150034442201 - 210 = 150034441177 is a prime.

It is not an unprimeable number, because it can be changed into a prime (150034441201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10716745865 + ... + 10716745878.

It is an arithmetic number, because the mean of its divisors is an integer number (42866983488).

Almost surely, 2150034442201 is an apocalyptic number.

It is an amenable number.

150034442201 is a deficient number, since it is larger than the sum of its proper divisors (21433491751).

150034442201 is an equidigital number, since it uses as much as digits as its factorization.

150034442201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21433491750.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 150034442201 its reverse (102244430051), we get a palindrome (252278872252).

The spelling of 150034442201 in words is "one hundred fifty billion, thirty-four million, four hundred forty-two thousand, two hundred one".

Divisors: 1 7 21433491743 150034442201