150041440105001 has 2 divisors, whose sum is σ = 150041440105002. Its totient is φ = 150041440105000.

The previous prime is 150041440104977. The next prime is 150041440105009. The reversal of 150041440105001 is 100501044140051.

150041440105001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122893963920025 + 27147476184976 = 11085755^2 + 5210324^2 .

It is an emirp because it is prime and its reverse (100501044140051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150041440105001 is a prime.

It is a super-3 number, since 3×150041440105001³ (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (150041440105009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75020720052500 + 75020720052501.

It is an arithmetic number, because the mean of its divisors is an integer number (75020720052501).

Almost surely, 2^{150041440105001} is an apocalyptic number.

It is an amenable number.

150041440105001 is a deficient number, since it is larger than the sum of its proper divisors (1).

150041440105001 is an equidigital number, since it uses as much as digits as its factorization.

150041440105001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1600, while the sum is 26.

Adding to 150041440105001 its reverse (100501044140051), we get a palindrome (250542484245052).

The spelling of 150041440105001 in words is "one hundred fifty trillion, forty-one billion, four hundred forty million, one hundred five thousand, one".