Base | Representation |
---|---|
bin | 1000101110111101011… |
… | …0011111110100000001 |
3 | 112100021212021101111011 |
4 | 2023233112133310001 |
5 | 4424242400241121 |
6 | 152532435120521 |
7 | 13561146355645 |
oct | 2135726376401 |
9 | 470255241434 |
10 | 150044540161 |
11 | 586a725a8aa |
12 | 250b5743141 |
13 | 111c2875699 |
14 | 7395666c25 |
15 | 3d8297b7e1 |
hex | 22ef59fd01 |
150044540161 has 2 divisors, whose sum is σ = 150044540162. Its totient is φ = 150044540160.
The previous prime is 150044540153. The next prime is 150044540179. The reversal of 150044540161 is 161045440051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126522490000 + 23522050161 = 355700^2 + 153369^2 .
It is an emirp because it is prime and its reverse (161045440051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150044540161 - 23 = 150044540153 is a prime.
It is not a weakly prime, because it can be changed into another prime (150044544161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75022270080 + 75022270081.
It is an arithmetic number, because the mean of its divisors is an integer number (75022270081).
Almost surely, 2150044540161 is an apocalyptic number.
It is an amenable number.
150044540161 is a deficient number, since it is larger than the sum of its proper divisors (1).
150044540161 is an equidigital number, since it uses as much as digits as its factorization.
150044540161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 150044540161 in words is "one hundred fifty billion, forty-four million, five hundred forty thousand, one hundred sixty-one".
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