Base | Representation |
---|---|
bin | 1000101110111101100… |
… | …1011100010110010001 |
3 | 112100021220201121210122 |
4 | 2023233121130112101 |
5 | 4424243044444101 |
6 | 152532503440025 |
7 | 13561156053245 |
oct | 2135731342621 |
9 | 470256647718 |
10 | 150045312401 |
11 | 586a7738016 |
12 | 250b5a56015 |
13 | 111c2a8602a |
14 | 73957c8425 |
15 | 3d82a8051b |
hex | 22ef65c591 |
150045312401 has 2 divisors, whose sum is σ = 150045312402. Its totient is φ = 150045312400.
The previous prime is 150045312397. The next prime is 150045312419. The reversal of 150045312401 is 104213540051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 134486492176 + 15558820225 = 366724^2 + 124735^2 .
It is a cyclic number.
It is not a de Polignac number, because 150045312401 - 22 = 150045312397 is a prime.
It is a super-3 number, since 3×1500453124013 (a number of 35 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (150045312421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75022656200 + 75022656201.
It is an arithmetic number, because the mean of its divisors is an integer number (75022656201).
Almost surely, 2150045312401 is an apocalyptic number.
It is an amenable number.
150045312401 is a deficient number, since it is larger than the sum of its proper divisors (1).
150045312401 is an equidigital number, since it uses as much as digits as its factorization.
150045312401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 150045312401 its reverse (104213540051), we get a palindrome (254258852452).
The spelling of 150045312401 in words is "one hundred fifty billion, forty-five million, three hundred twelve thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •