Base | Representation |
---|---|
bin | 100010000111100101101000… |
… | …011011010001011101010001 |
3 | 201200022010020122120221102001 |
4 | 202013211220123101131101 |
5 | 124132000142221301314 |
6 | 1251050154311554001 |
7 | 43415055250350265 |
oct | 4207455033213521 |
9 | 650263218527361 |
10 | 150055024400209 |
11 | 438a2a84390585 |
12 | 149b580408b901 |
13 | 659618852b6c6 |
14 | 290a9b81600a5 |
15 | 125341ee4a674 |
hex | 8879686d1751 |
150055024400209 has 2 divisors, whose sum is σ = 150055024400210. Its totient is φ = 150055024400208.
The previous prime is 150055024400159. The next prime is 150055024400243. The reversal of 150055024400209 is 902004420550051.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 144883880179984 + 5171144220225 = 12036772^2 + 2274015^2 .
It is a cyclic number.
It is not a de Polignac number, because 150055024400209 - 27 = 150055024400081 is a prime.
It is not a weakly prime, because it can be changed into another prime (150055024400609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027512200104 + 75027512200105.
It is an arithmetic number, because the mean of its divisors is an integer number (75027512200105).
Almost surely, 2150055024400209 is an apocalyptic number.
It is an amenable number.
150055024400209 is a deficient number, since it is larger than the sum of its proper divisors (1).
150055024400209 is an equidigital number, since it uses as much as digits as its factorization.
150055024400209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
The spelling of 150055024400209 in words is "one hundred fifty trillion, fifty-five billion, twenty-four million, four hundred thousand, two hundred nine".
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