Base | Representation |
---|---|
bin | 11011111101011111… |
… | …10000011001100001 |
3 | 1102202011111121010010 |
4 | 31332233300121201 |
5 | 221220401200423 |
6 | 10521321155133 |
7 | 1040665241064 |
oct | 157657603141 |
9 | 42664447103 |
10 | 15011350113 |
11 | 6403574581 |
12 | 2aab32baa9 |
13 | 1552cc12b6 |
14 | a2593a8db |
15 | 5ccd07693 |
hex | 37ebf0661 |
15011350113 has 8 divisors (see below), whose sum is σ = 20392777728. Its totient is φ = 9818744624.
The previous prime is 15011350111. The next prime is 15011350169. The reversal of 15011350113 is 31105311051.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15011350113 - 21 = 15011350111 is a prime.
It is a super-2 number, since 2×150113501132 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 15011350113.
It is not an unprimeable number, because it can be changed into a prime (15011350111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47205345 + ... + 47205662.
It is an arithmetic number, because the mean of its divisors is an integer number (2549097216).
Almost surely, 215011350113 is an apocalyptic number.
It is an amenable number.
15011350113 is a deficient number, since it is larger than the sum of its proper divisors (5381427615).
15011350113 is an equidigital number, since it uses as much as digits as its factorization.
15011350113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94411063.
The product of its (nonzero) digits is 225, while the sum is 21.
Adding to 15011350113 its reverse (31105311051), we get a palindrome (46116661164).
The spelling of 15011350113 in words is "fifteen billion, eleven million, three hundred fifty thousand, one hundred thirteen".
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