150141203000121 has 4 divisors (see below), whose sum is σ = 200188270666832. Its totient is φ = 100094135333412.

The previous prime is 150141203000111. The next prime is 150141203000143. The reversal of 150141203000121 is 121000302141051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 150141203000121 - 2⁹ = 150141202999609 is a prime.

It is a super-2 number, since 2×150141203000121² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150141203000101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25023533833351 + ... + 25023533833356.

It is an arithmetic number, because the mean of its divisors is an integer number (50047067666708).

Almost surely, 2^{150141203000121} is an apocalyptic number.

It is an amenable number.

150141203000121 is a deficient number, since it is larger than the sum of its proper divisors (50047067666711).

150141203000121 is an equidigital number, since it uses as much as digits as its factorization.

150141203000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50047067666710.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 150141203000121 its reverse (121000302141051), we get a palindrome (271141505141172).

The spelling of 150141203000121 in words is "one hundred fifty trillion, one hundred forty-one billion, two hundred three million, one hundred twenty-one", and thus it is an aban number.