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150143314047 = 3591597531163
BaseRepresentation
bin1000101111010100111…
…1010010100001111111
3112100112202010121210020
42023311033102201333
54424443142022142
6152550324143223
713563456053316
oct2136517224177
9470482117706
10150143314047
1158747a94111
1225122837b13
131120a17a07c
1473a481927d
153d8b48ccec
hex22f53d287f

150143314047 has 16 divisors (see below), whose sum is σ = 203712017280. Its totient is φ = 98337208032.

The previous prime is 150143314039. The next prime is 150143314051. The reversal of 150143314047 is 740413341051.

It is not a de Polignac number, because 150143314047 - 23 = 150143314039 is a prime.

It is a super-3 number, since 3×1501433140473 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150143313999 and 150143314017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150143316047) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17088 + ... + 548250.

It is an arithmetic number, because the mean of its divisors is an integer number (12732001080).

Almost surely, 2150143314047 is an apocalyptic number.

150143314047 is a deficient number, since it is larger than the sum of its proper divisors (53568703233).

150143314047 is a wasteful number, since it uses less digits than its factorization.

150143314047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 532822.

The product of its (nonzero) digits is 20160, while the sum is 33.

Adding to 150143314047 its reverse (740413341051), we get a palindrome (890556655098).

The spelling of 150143314047 in words is "one hundred fifty billion, one hundred forty-three million, three hundred fourteen thousand, forty-seven".

Divisors: 1 3 59 177 1597 4791 94223 282669 531163 1593489 31338617 94015851 848267311 2544801933 50047771349 150143314047