Base | Representation |
---|---|
bin | 1000101111010100111… |
… | …1010010100001111111 |
3 | 112100112202010121210020 |
4 | 2023311033102201333 |
5 | 4424443142022142 |
6 | 152550324143223 |
7 | 13563456053316 |
oct | 2136517224177 |
9 | 470482117706 |
10 | 150143314047 |
11 | 58747a94111 |
12 | 25122837b13 |
13 | 1120a17a07c |
14 | 73a481927d |
15 | 3d8b48ccec |
hex | 22f53d287f |
150143314047 has 16 divisors (see below), whose sum is σ = 203712017280. Its totient is φ = 98337208032.
The previous prime is 150143314039. The next prime is 150143314051. The reversal of 150143314047 is 740413341051.
It is not a de Polignac number, because 150143314047 - 23 = 150143314039 is a prime.
It is a super-3 number, since 3×1501433140473 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 150143313999 and 150143314017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150143316047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17088 + ... + 548250.
It is an arithmetic number, because the mean of its divisors is an integer number (12732001080).
Almost surely, 2150143314047 is an apocalyptic number.
150143314047 is a deficient number, since it is larger than the sum of its proper divisors (53568703233).
150143314047 is a wasteful number, since it uses less digits than its factorization.
150143314047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 532822.
The product of its (nonzero) digits is 20160, while the sum is 33.
Adding to 150143314047 its reverse (740413341051), we get a palindrome (890556655098).
The spelling of 150143314047 in words is "one hundred fifty billion, one hundred forty-three million, three hundred fourteen thousand, forty-seven".
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