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150200133513 = 350066711171
BaseRepresentation
bin1000101111100010100…
…0000010011110001001
3112100200201001100102220
42023320220002132021
54430102213233023
6153000114044253
713565046032613
oct2137050023611
9470621040386
10150200133513
1158777072451
1225139879689
1311218b82461
1473ac1a9db3
153d914633e3
hex22f8a02789

150200133513 has 4 divisors (see below), whose sum is σ = 200266844688. Its totient is φ = 100133422340.

The previous prime is 150200133491. The next prime is 150200133571. The reversal of 150200133513 is 315331002051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150200133513 - 214 = 150200117129 is a prime.

It is not an unprimeable number, because it can be changed into a prime (150200133113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25033355583 + ... + 25033355588.

It is an arithmetic number, because the mean of its divisors is an integer number (50066711172).

Almost surely, 2150200133513 is an apocalyptic number.

It is an amenable number.

150200133513 is a deficient number, since it is larger than the sum of its proper divisors (50066711175).

150200133513 is an equidigital number, since it uses as much as digits as its factorization.

150200133513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50066711174.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 150200133513 its reverse (315331002051), we get a palindrome (465531135564).

The spelling of 150200133513 in words is "one hundred fifty billion, two hundred million, one hundred thirty-three thousand, five hundred thirteen".

Divisors: 1 3 50066711171 150200133513