Base | Representation |
---|---|
bin | 10001111010000… |
… | …00101001001011 |
3 | 101110122111221211 |
4 | 20331000221023 |
5 | 301423224042 |
6 | 22523313551 |
7 | 3502526242 |
oct | 1075005113 |
9 | 343574854 |
10 | 150211147 |
11 | 77876949 |
12 | 4237b8b7 |
13 | 25174048 |
14 | 15d41959 |
15 | d2c2017 |
hex | 8f40a4b |
150211147 has 2 divisors, whose sum is σ = 150211148. Its totient is φ = 150211146.
The previous prime is 150211141. The next prime is 150211181. The reversal of 150211147 is 741112051.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150211147 is a prime.
It is not a weakly prime, because it can be changed into another prime (150211141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75105573 + 75105574.
It is an arithmetic number, because the mean of its divisors is an integer number (75105574).
Almost surely, 2150211147 is an apocalyptic number.
150211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
150211147 is an equidigital number, since it uses as much as digits as its factorization.
150211147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 280, while the sum is 22.
The square root of 150211147 is about 12256.0657227350. The cubic root of 150211147 is about 531.5784756690.
Adding to 150211147 its reverse (741112051), we get a palindrome (891323198).
The spelling of 150211147 in words is "one hundred fifty million, two hundred eleven thousand, one hundred forty-seven".
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