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150225035405033 is a prime number
BaseRepresentation
bin100010001010000011111101…
…110111110010011011101001
3201200220101002000021211022102
4202022003331313302123221
5124142241333030430113
61251300232321503145
743433254264141421
oct4212037567623351
9650811060254272
10150225035405033
1143959097144846
1214a227504a1ab5
1365a9210839804
142914d0545d481
151257a7071b758
hex88a0fddf26e9

150225035405033 has 2 divisors, whose sum is σ = 150225035405034. Its totient is φ = 150225035405032.

The previous prime is 150225035404987. The next prime is 150225035405077. The reversal of 150225035405033 is 330504530522051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141429463177744 + 8795572227289 = 11892412^2 + 2965733^2 .

It is a cyclic number.

It is not a de Polignac number, because 150225035405033 - 228 = 150224766969577 is a prime.

It is a super-2 number, since 2×1502250354050332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (150225035405083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75112517702516 + 75112517702517.

It is an arithmetic number, because the mean of its divisors is an integer number (75112517702517).

Almost surely, 2150225035405033 is an apocalyptic number.

It is an amenable number.

150225035405033 is a deficient number, since it is larger than the sum of its proper divisors (1).

150225035405033 is an equidigital number, since it uses as much as digits as its factorization.

150225035405033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270000, while the sum is 38.

Adding to 150225035405033 its reverse (330504530522051), we get a palindrome (480729565927084).

The spelling of 150225035405033 in words is "one hundred fifty trillion, two hundred twenty-five billion, thirty-five million, four hundred five thousand, thirty-three".