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15025412021132 = 225716578551673
BaseRepresentation
bin1101101010100110000001…
…0110001001101110001100
31222012102012210112210210102
43122221200112021232030
53432134020434134012
651542325021230232
73110356500620552
oct332514026115614
958172183483712
1015025412021132
114873272413137
121828038102378
1384cb75c16086
1439d33b871bd2
151b0ca35c22c2
hexdaa60589b8c

15025412021132 has 12 divisors (see below), whose sum is σ = 26340520902696. Its totient is φ = 7499548906080.

The previous prime is 15025412021111. The next prime is 15025412021141. The reversal of 15025412021132 is 23112021452051.

It is a super-2 number, since 2×150254120211322 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15025412021095 and 15025412021104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3289273553 + ... + 3289278120.

It is an arithmetic number, because the mean of its divisors is an integer number (2195043408558).

Almost surely, 215025412021132 is an apocalyptic number.

It is an amenable number.

15025412021132 is a deficient number, since it is larger than the sum of its proper divisors (11315108881564).

15025412021132 is a wasteful number, since it uses less digits than its factorization.

15025412021132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6578552248 (or 6578552246 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 15025412021132 its reverse (23112021452051), we get a palindrome (38137433473183).

The spelling of 15025412021132 in words is "fifteen trillion, twenty-five billion, four hundred twelve million, twenty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 571 1142 2284 6578551673 13157103346 26314206692 3756353005283 7512706010566 15025412021132