Base | Representation |
---|---|
bin | 1101101010100110000001… |
… | …0110001001101110001100 |
3 | 1222012102012210112210210102 |
4 | 3122221200112021232030 |
5 | 3432134020434134012 |
6 | 51542325021230232 |
7 | 3110356500620552 |
oct | 332514026115614 |
9 | 58172183483712 |
10 | 15025412021132 |
11 | 4873272413137 |
12 | 1828038102378 |
13 | 84cb75c16086 |
14 | 39d33b871bd2 |
15 | 1b0ca35c22c2 |
hex | daa60589b8c |
15025412021132 has 12 divisors (see below), whose sum is σ = 26340520902696. Its totient is φ = 7499548906080.
The previous prime is 15025412021111. The next prime is 15025412021141. The reversal of 15025412021132 is 23112021452051.
It is a super-2 number, since 2×150254120211322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15025412021095 and 15025412021104.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3289273553 + ... + 3289278120.
It is an arithmetic number, because the mean of its divisors is an integer number (2195043408558).
Almost surely, 215025412021132 is an apocalyptic number.
It is an amenable number.
15025412021132 is a deficient number, since it is larger than the sum of its proper divisors (11315108881564).
15025412021132 is a wasteful number, since it uses less digits than its factorization.
15025412021132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6578552248 (or 6578552246 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 15025412021132 its reverse (23112021452051), we get a palindrome (38137433473183).
The spelling of 15025412021132 in words is "fifteen trillion, twenty-five billion, four hundred twelve million, twenty-one thousand, one hundred thirty-two".
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