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15030314121 = 35010104707
BaseRepresentation
bin11011111111110000…
…00110010010001001
31102210111012001211210
431333320012102021
5221240230022441
610523235443333
71041315363534
oct157770062211
942714161753
1015030314121
116413247509
122ab5756549
131556c00cc4
14a28275a1b
155ce801616
hex37fe06489

15030314121 has 4 divisors (see below), whose sum is σ = 20040418832. Its totient is φ = 10020209412.

The previous prime is 15030314119. The next prime is 15030314141. The reversal of 15030314121 is 12141303051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12141303051 = 34047101017.

It is not a de Polignac number, because 15030314121 - 21 = 15030314119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15030314111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2505052351 + ... + 2505052356.

It is an arithmetic number, because the mean of its divisors is an integer number (5010104708).

Almost surely, 215030314121 is an apocalyptic number.

It is an amenable number.

15030314121 is a deficient number, since it is larger than the sum of its proper divisors (5010104711).

15030314121 is an equidigital number, since it uses as much as digits as its factorization.

15030314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5010104710.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 15030314121 its reverse (12141303051), we get a palindrome (27171617172).

The spelling of 15030314121 in words is "fifteen billion, thirty million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 5010104707 15030314121