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150365031043 = 1049143341307
BaseRepresentation
bin1000110000001001110…
…1000100101010000011
3112101010012100000022211
42030002131010222003
54430421421443133
6153024324242551
713602120450463
oct2140235045203
9471105300284
10150365031043
115885115a3a7
1225184b40457
1311244099166
1473c6051ba3
153da0b86bcd
hex2302744a83

150365031043 has 4 divisors (see below), whose sum is σ = 150508373400. Its totient is φ = 150221688688.

The previous prime is 150365030953. The next prime is 150365031071. The reversal of 150365031043 is 340130563051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150365031043 - 221 = 150362933891 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150365030996 and 150365031014.

It is not an unprimeable number, because it can be changed into a prime (150365035043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71669605 + ... + 71671702.

It is an arithmetic number, because the mean of its divisors is an integer number (37627093350).

Almost surely, 2150365031043 is an apocalyptic number.

150365031043 is a deficient number, since it is larger than the sum of its proper divisors (143342357).

150365031043 is a wasteful number, since it uses less digits than its factorization.

150365031043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143342356.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 150365031043 its reverse (340130563051), we get a palindrome (490495594094).

The spelling of 150365031043 in words is "one hundred fifty billion, three hundred sixty-five million, thirty-one thousand, forty-three".

Divisors: 1 1049 143341307 150365031043