Base | Representation |
---|---|
bin | 1101101011011101100100… |
… | …1011000001110111110011 |
3 | 1222020211201001011101100102 |
4 | 3122313121023001313303 |
5 | 3432410040424103134 |
6 | 51553232433543015 |
7 | 3111425152025603 |
oct | 332673113016763 |
9 | 58224631141312 |
10 | 15040324050419 |
11 | 487962490a488 |
12 | 182aaba114a6b |
13 | 8513b1470a45 |
14 | 39dd54116c03 |
15 | 1b137780b37e |
hex | dadd92c1df3 |
15040324050419 has 2 divisors, whose sum is σ = 15040324050420. Its totient is φ = 15040324050418.
The previous prime is 15040324050379. The next prime is 15040324050449. The reversal of 15040324050419 is 91405042304051.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15040324050419 is a prime.
It is a super-2 number, since 2×150403240504192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15040324050449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520162025209 + 7520162025210.
It is an arithmetic number, because the mean of its divisors is an integer number (7520162025210).
Almost surely, 215040324050419 is an apocalyptic number.
15040324050419 is a deficient number, since it is larger than the sum of its proper divisors (1).
15040324050419 is an equidigital number, since it uses as much as digits as its factorization.
15040324050419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 15040324050419 in words is "fifteen trillion, forty billion, three hundred twenty-four million, fifty thousand, four hundred nineteen".
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