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15042434441 = 145910310099
BaseRepresentation
bin11100000001001100…
…10101010110001001
31102211022222211210112
432000212111112021
5221301330400231
610524351324105
71041523403666
oct160046252611
942738884715
1015042434441
11641a075701
122ab9820635
1315595859a8
14a29b0ca6d
155d08e792b
hex380995589

15042434441 has 4 divisors (see below), whose sum is σ = 15052746000. Its totient is φ = 15032122884.

The previous prime is 15042434431. The next prime is 15042434453. The reversal of 15042434441 is 14443424051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15042434441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 15042434398 and 15042434407.

It is not an unprimeable number, because it can be changed into a prime (15042434431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5153591 + ... + 5156508.

It is an arithmetic number, because the mean of its divisors is an integer number (3763186500).

Almost surely, 215042434441 is an apocalyptic number.

It is an amenable number.

15042434441 is a deficient number, since it is larger than the sum of its proper divisors (10311559).

15042434441 is a wasteful number, since it uses less digits than its factorization.

15042434441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10311558.

The product of its (nonzero) digits is 30720, while the sum is 32.

Adding to 15042434441 its reverse (14443424051), we get a palindrome (29485858492).

The spelling of 15042434441 in words is "fifteen billion, forty-two million, four hundred thirty-four thousand, four hundred forty-one".

Divisors: 1 1459 10310099 15042434441