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150483433 is a prime number
BaseRepresentation
bin10001111100000…
…11000111101001
3101111011100110111
420332003013221
5302010432213
622533214321
73505042132
oct1076030751
9344140414
10150483433
1177a42481
12424913a1
132523ac69
1415db2c89
15d327a3d
hex8f831e9

150483433 has 2 divisors, whose sum is σ = 150483434. Its totient is φ = 150483432.

The previous prime is 150483413. The next prime is 150483449. The reversal of 150483433 is 334384051.

150483433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 147671104 + 2812329 = 12152^2 + 1677^2 .

It is a cyclic number.

It is not a de Polignac number, because 150483433 - 29 = 150482921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 150483395 and 150483404.

It is not a weakly prime, because it can be changed into another prime (150483413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75241716 + 75241717.

It is an arithmetic number, because the mean of its divisors is an integer number (75241717).

Almost surely, 2150483433 is an apocalyptic number.

It is an amenable number.

150483433 is a deficient number, since it is larger than the sum of its proper divisors (1).

150483433 is an equidigital number, since it uses as much as digits as its factorization.

150483433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

The square root of 150483433 is about 12267.1689072907. The cubic root of 150483433 is about 531.8994771629.

It can be divided in two parts, 15048 and 3433, that added together give a palindrome (18481).

The spelling of 150483433 in words is "one hundred fifty million, four hundred eighty-three thousand, four hundred thirty-three".