Base | Representation |
---|---|
bin | 1000110000110011110… |
… | …1111010110001000001 |
3 | 112101120111020011111020 |
4 | 2030030331322301001 |
5 | 4431302100212231 |
6 | 153054024540053 |
7 | 13606361621046 |
oct | 2141475726101 |
9 | 471514204436 |
10 | 150541413441 |
11 | 58931781081 |
12 | 25214021629 |
13 | 112717a4543 |
14 | 74016471cd |
15 | 3db13c8396 |
hex | 230cf7ac41 |
150541413441 has 4 divisors (see below), whose sum is σ = 200721884592. Its totient is φ = 100360942292.
The previous prime is 150541413433. The next prime is 150541413443. The reversal of 150541413441 is 144314145051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 150541413441 - 23 = 150541413433 is a prime.
It is not an unprimeable number, because it can be changed into a prime (150541413443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25090235571 + ... + 25090235576.
It is an arithmetic number, because the mean of its divisors is an integer number (50180471148).
Almost surely, 2150541413441 is an apocalyptic number.
It is an amenable number.
150541413441 is a deficient number, since it is larger than the sum of its proper divisors (50180471151).
150541413441 is an equidigital number, since it uses as much as digits as its factorization.
150541413441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50180471150.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 150541413441 its reverse (144314145051), we get a palindrome (294855558492).
The spelling of 150541413441 in words is "one hundred fifty billion, five hundred forty-one million, four hundred thirteen thousand, four hundred forty-one".
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