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15063306131 = 31485913101
BaseRepresentation
bin11100000011101011…
…11100111110010011
31102212210021020101002
432001311330332103
5221322201244011
610530414532215
71042165663256
oct160165747623
942783236332
1015063306131
11642a930935
122b0480706b
1315609b2ac3
14a2c7c309d
155d266bc3b
hex381d7cf93

15063306131 has 4 divisors (see below), whose sum is σ = 15549219264. Its totient is φ = 14577393000.

The previous prime is 15063306113. The next prime is 15063306133. The reversal of 15063306131 is 13160336051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15063306131 is a prime.

It is a super-2 number, since 2×150633061312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15063306094 and 15063306103.

It is not an unprimeable number, because it can be changed into a prime (15063306133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242956520 + ... + 242956581.

It is an arithmetic number, because the mean of its divisors is an integer number (3887304816).

Almost surely, 215063306131 is an apocalyptic number.

15063306131 is a deficient number, since it is larger than the sum of its proper divisors (485913133).

15063306131 is an equidigital number, since it uses as much as digits as its factorization.

15063306131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 485913132.

The product of its (nonzero) digits is 4860, while the sum is 29.

The spelling of 15063306131 in words is "fifteen billion, sixty-three million, three hundred six thousand, one hundred thirty-one".

Divisors: 1 31 485913101 15063306131