Search a number
-
+
15063412129897 is a prime number
BaseRepresentation
bin1101101100110011100101…
…0101000100000001101001
31222100001022002110100021011
43123030321111010001221
53433244332001124042
652012011435343521
73113203252331635
oct333147125040151
958301262410234
1015063412129897
1148883a24992aa
1218334822b1ba1
1385362085b931
143a11045b1dc5
151b1c79718a17
hexdb339544069

15063412129897 has 2 divisors, whose sum is σ = 15063412129898. Its totient is φ = 15063412129896.

The previous prime is 15063412129847. The next prime is 15063412129921. The reversal of 15063412129897 is 79892121436051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12210474933801 + 2852937196096 = 3494349^2 + 1689064^2 .

It is an emirp because it is prime and its reverse (79892121436051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15063412129897 - 211 = 15063412127849 is a prime.

It is not a weakly prime, because it can be changed into another prime (15063412129847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7531706064948 + 7531706064949.

It is an arithmetic number, because the mean of its divisors is an integer number (7531706064949).

It is a 2-persistent number, because it is pandigital, and so is 2⋅15063412129897 = 30126824259794, but 3⋅15063412129897 = 45190236389691 is not.

Almost surely, 215063412129897 is an apocalyptic number.

It is an amenable number.

15063412129897 is a deficient number, since it is larger than the sum of its proper divisors (1).

15063412129897 is an equidigital number, since it uses as much as digits as its factorization.

15063412129897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6531840, while the sum is 58.

The spelling of 15063412129897 in words is "fifteen trillion, sixty-three billion, four hundred twelve million, one hundred twenty-nine thousand, eight hundred ninety-seven".