Base | Representation |
---|---|
bin | 1000110001001111000… |
… | …1010110100110110001 |
3 | 112101212110000102021202 |
4 | 2030103301112212301 |
5 | 4432020310410423 |
6 | 153113223300545 |
7 | 13612246063142 |
oct | 2142361264661 |
9 | 471773012252 |
10 | 150655560113 |
11 | 58990155173 |
12 | 252462aa755 |
13 | 1128c32c156 |
14 | 741287bac9 |
15 | 3dbb424728 |
hex | 2313c569b1 |
150655560113 has 2 divisors, whose sum is σ = 150655560114. Its totient is φ = 150655560112.
The previous prime is 150655560079. The next prime is 150655560163. The reversal of 150655560113 is 311065556051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 150177175729 + 478384384 = 387527^2 + 21872^2 .
It is an emirp because it is prime and its reverse (311065556051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150655560113 - 214 = 150655543729 is a prime.
It is not a weakly prime, because it can be changed into another prime (150655560163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75327780056 + 75327780057.
It is an arithmetic number, because the mean of its divisors is an integer number (75327780057).
Almost surely, 2150655560113 is an apocalyptic number.
It is an amenable number.
150655560113 is a deficient number, since it is larger than the sum of its proper divisors (1).
150655560113 is an equidigital number, since it uses as much as digits as its factorization.
150655560113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67500, while the sum is 38.
The spelling of 150655560113 in words is "one hundred fifty billion, six hundred fifty-five million, five hundred sixty thousand, one hundred thirteen".
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