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151001313 = 350333771
BaseRepresentation
bin10010000000000…
…01100011100001
3101112010122212020
421000001203201
5302124020223
622552252053
73512330031
oct1100014341
9345118766
10151001313
1178266581
12426a1029
132538c8b8
14160a98c1
15d3cb1e3
hex90018e1

151001313 has 4 divisors (see below), whose sum is σ = 201335088. Its totient is φ = 100667540.

The previous prime is 151001299. The next prime is 151001321. The reversal of 151001313 is 313100151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 151001313 - 214 = 150984929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151001292 and 151001301.

It is not an unprimeable number, because it can be changed into a prime (151021313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25166883 + ... + 25166888.

It is an arithmetic number, because the mean of its divisors is an integer number (50333772).

Almost surely, 2151001313 is an apocalyptic number.

It is an amenable number.

151001313 is a deficient number, since it is larger than the sum of its proper divisors (50333775).

151001313 is an equidigital number, since it uses as much as digits as its factorization.

151001313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50333774.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 151001313 is about 12288.2591525407. The cubic root of 151001313 is about 532.5089456056.

Adding to 151001313 its reverse (313100151), we get a palindrome (464101464).

The spelling of 151001313 in words is "one hundred fifty-one million, one thousand, three hundred thirteen".

Divisors: 1 3 50333771 151001313