Base | Representation |
---|---|
bin | 100010010101101010001110… |
… | …101110010000000100000001 |
3 | 201210201120021020210101111121 |
4 | 202111222032232100010001 |
5 | 124243321111321113131 |
6 | 1253110322003312241 |
7 | 43544660542123123 |
oct | 4225521656200401 |
9 | 653646236711447 |
10 | 151022034551041 |
11 | 441360a3405515 |
12 | 14b310b997b681 |
13 | 6636416b93024 |
14 | 2941711039213 |
15 | 126d66a34b911 |
hex | 895a8eb90101 |
151022034551041 has 4 divisors (see below), whose sum is σ = 156229690914900. Its totient is φ = 145814378187184.
The previous prime is 151022034551033. The next prime is 151022034551107. The reversal of 151022034551041 is 140155430220151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 49655980890000 + 101366053661041 = 7046700^2 + 10068071^2 .
It is a cyclic number.
It is not a de Polignac number, because 151022034551041 - 23 = 151022034551033 is a prime.
It is a super-3 number, since 3×1510220345510413 (a number of 44 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151022034550988 and 151022034551006.
It is not an unprimeable number, because it can be changed into a prime (151022034551741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2603828181886 + ... + 2603828181943.
It is an arithmetic number, because the mean of its divisors is an integer number (39057422728725).
Almost surely, 2151022034551041 is an apocalyptic number.
It is an amenable number.
151022034551041 is a deficient number, since it is larger than the sum of its proper divisors (5207656363859).
151022034551041 is an equidigital number, since it uses as much as digits as its factorization.
151022034551041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5207656363858.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 151022034551041 its reverse (140155430220151), we get a palindrome (291177464771192).
The spelling of 151022034551041 in words is "one hundred fifty-one trillion, twenty-two billion, thirty-four million, five hundred fifty-one thousand, forty-one".
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