15103031113 has 4 divisors (see below), whose sum is σ = 15106060948. Its totient is φ = 15100001280.

The previous prime is 15103031107. The next prime is 15103031117. The reversal of 15103031113 is 31113030151.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7189683264 + 7913347849 = 84792^2 + 88957^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15103031113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15103031117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1507428 + ... + 1517413.

It is an arithmetic number, because the mean of its divisors is an integer number (3776515237).

Almost surely, 2^15103031113 is an apocalyptic number.

It is an amenable number.

15103031113 is a deficient number, since it is larger than the sum of its proper divisors (3029835).

15103031113 is an equidigital number, since it uses as much as digits as its factorization.

15103031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3029834.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 15103031113 its reverse (31113030151), we get a palindrome (46216061264).

The spelling of 15103031113 in words is "fifteen billion, one hundred three million, thirty-one thousand, one hundred thirteen".