Base | Representation |
---|---|
bin | 100010010111000101110000… |
… | …000010011111011110001001 |
3 | 201211001221220211010012022002 |
4 | 202113011300002133132021 |
5 | 124301423340311324040 |
6 | 1253223413111040345 |
7 | 43555040003551610 |
oct | 4227056002373611 |
9 | 654057824105262 |
10 | 151120304011145 |
11 | 44173840a09357 |
12 | 14b481640700b5 |
13 | 6642777cc2561 |
14 | 2946394304877 |
15 | 1270ebc69da15 |
hex | 89717009f789 |
151120304011145 has 16 divisors (see below), whose sum is σ = 207487020476928. Its totient is φ = 103507192405440.
The previous prime is 151120304011139. The next prime is 151120304011153. The reversal of 151120304011145 is 541110403021151.
It is not a de Polignac number, because 151120304011145 - 220 = 151120302962569 is a prime.
It is a super-2 number, since 2×1511203040111452 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2461612961 + ... + 2461674350.
It is an arithmetic number, because the mean of its divisors is an integer number (12967938779808).
Almost surely, 2151120304011145 is an apocalyptic number.
It is an amenable number.
151120304011145 is a deficient number, since it is larger than the sum of its proper divisors (56366716465783).
151120304011145 is an equidigital number, since it uses as much as digits as its factorization.
151120304011145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4923288200.
The product of its (nonzero) digits is 2400, while the sum is 29.
Adding to 151120304011145 its reverse (541110403021151), we get a palindrome (692230707032296).
The spelling of 151120304011145 in words is "one hundred fifty-one trillion, one hundred twenty billion, three hundred four million, eleven thousand, one hundred forty-five".
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