Base | Representation |
---|---|
bin | 100010010111011000000111… |
… | …111100110100111010011010 |
3 | 201211010211211201210220100012 |
4 | 202113120013330310322122 |
5 | 124302234241312011442 |
6 | 1253240434501441522 |
7 | 43556335621324514 |
oct | 4227300774647232 |
9 | 654124751726305 |
10 | 151140032532122 |
11 | 44181145174147 |
12 | 14b4bb4b1102a2 |
13 | 66445a03770ca |
14 | 294730651cbb4 |
15 | 1271774691582 |
hex | 897607f34e9a |
151140032532122 has 4 divisors (see below), whose sum is σ = 226710048798186. Its totient is φ = 75570016266060.
The previous prime is 151140032532109. The next prime is 151140032532227. The reversal of 151140032532122 is 221235230041151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 105879551868841 + 45260480663281 = 10289779^2 + 6727591^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37785008133029 + ... + 37785008133032.
Almost surely, 2151140032532122 is an apocalyptic number.
151140032532122 is a deficient number, since it is larger than the sum of its proper divisors (75570016266064).
151140032532122 is an equidigital number, since it uses as much as digits as its factorization.
151140032532122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75570016266063.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 151140032532122 its reverse (221235230041151), we get a palindrome (372375262573273).
The spelling of 151140032532122 in words is "one hundred fifty-one trillion, one hundred forty billion, thirty-two million, five hundred thirty-two thousand, one hundred twenty-two".
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